Question

Find the root of the equasion
(2y+1)^2–4y^2=5

Answer 1

the root of the equation is y=1

Explanation:

`(2y + 1)^(2) - 4 {y}^(2) = 5 \\ 4 {y}^(2) + 2 * 2y * 1 + {1}^(2) - 4 {y}^(2) = 5 \\ 4y + 1 = 5 \\ 4y = 5 - 1 \\ 4y = 4 \\ y = 1`