Question

Can someone help me?

Answer 1

9514 1404 393

Answer:

54w^7/v^17

Explanation:

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

a^-b = 1/a^b

a^0 = 1 . . . . for any a ≠ 0

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`3y^5y^(-5)v^(-9)\cdot6wv^(-8)\cdot3w^6=(3\cdot6\cdot3)v^(-9-8)w^(1+6)y^(5-5)\\\\=54v^(-17)w^7y^0=\boxed{(54w^7)/(v^(17))}`