Question

A ball is thrown vertically upward from the top of a building 96 feet tall with an initial

velocity of 80 feet per second. The distance s (in feet) of the ball from the ground after t
seconds is s(t) = 96+80t−16t
2
. After how many seconds does the ball strike the ground?

Answer 1

Answer: 5 second on the way down

Step-by-step explanation: i hope this helps plz tell me if its wrong so i can fix it