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The value of E for a system that performs 120 kJ of work on its surroundings and gains 50kJ of heat is ___?

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User Chester
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Answer:

-70

Step-by-step explanation:

work is being done, so 120 will be negative, heat is being gained, so 50 will be positive.

Delta E = -120 + 50 = -70 kJ

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User Celdor
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