Register

Let sin(2x) – sin(x) = 0, where 0 ≤ x < 2π. What are the possible solutions for x?

Let sin(2x) – sin(x) = 0, where 0 ≤ x < 2π. What are the possible solutions for x?
asked 223k views
0 votes
Let sin(2x) – sin(x) = 0, where 0 ≤ x < 2π. What are the possible solutions for x?

Let sin(2x) – sin(x) = 0, where 0 ≤ x < 2π. What are the possible solutions for-example-1
asked
User Brunobastosg
by
8.2k points

1 Answer

6 votes

Answer:

D. {0,π/3,π,5π/3}

Explanation:

answered
User Bbarnhart
by
8.1k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!