Question

Neutron stars have about the same mass as our sun but a much smaller diameter. The radius of a

neutron star is 10 x 10 m and its mass is 1.99 x 1030 kg. If you weigh 675 N on the earth, what
would you weigh on the surface of a neutron star?
A) 8.36 x 10^13 B) 7.42 x 10^13 C) 6.87 x 10^13 D) 9.16 x 10^13

Answer 1

`9.15* 10^(13)\ \text{N}`

Step-by-step explanation:

`m=\text{Mass of person}=(675)/(g)=(675)/(9.8)\ \text{kg}`

`g=\text{Acceleration due to gravity on Earth}=9.8\ \text{m/s}^2`

`r=\text{Radius the neutron star}=10\ \text{km}`

`M=\text{Mass of neutron star}=1.99* 10^(30)\ \text{kg}`

`G=\text{Gravitational constant}=6.674*10^(-11)\ \text{Nm}^2/\text{kg}^2`

Weight on neutron star would be

`W_n=(GmM)/(r^2)\\\Rightarrow W_n=(6.674* 10^(-11)* (675)/(9.8)* 1.99* 10^(30))/(10000^2)\\\Rightarrow W_n=9.15* 10^(13)\ \text{N}`

Weight of the person on the neutron star would be
`9.15* 10^(13)\ \text{N}`