Question

You have discovered the 1020 steel used to make a part should be strengthened by 10%. a. What strain is needed to increase the strength

Answer 1

The answer is "
`\bold{186 * \varepsilon \ 10^9}`".

Step-by-step explanation:

Given value:

`\to n= 10 \% \\\\`

`= 0.10\\`

`\text{From the properties of 1020 steel:}\\\\\to yield \ power (\sigma \ y) = 350 \ MPa\\\\`

`= 350 * 10^6 \ (N)/(m^2)\\\\`

`\to elasticity(E) \ Modulus = 186 \ GPa`

`= 186 * 10^9 \ (N)/(m^e)\\\\`

Strength must be improved by pressure:
`\varepsilon`

`\to \sigma = E * \varepsilon`

`= 186 * \varepsilon * 10^9\\\\= 186 \ \varepsilon * 10^9`