Question

A sequence is shown below.

32, 26, 20, 14...
Which explicit formula can be used to determine the nth term in the sequence?
a^n =6n+38
a^n= -6n+38
a^n= -6n+32
a^n= 6n+32​

Answer 1

a^n = -6n + 32

Explanation:

32 - 6 = 26

26 - 6 = 32 - 6.2 = 20

20 - 6 = 32 - 6.3 = 14

-> a^n = -6n + 32