Help me please and don't spam

Question

asked Apr 18, 2021 113k views

1 Answer

PRTJ · Answer 1 · 2021-04-24T06:33:59+0000

$\sqrt{ ({ - 1 - 7})^(2) + ({2 - a})^(2) } = \sqrt{ ({ - 1 - a})^(2) + ({2 - ( - 3)})^(2) } \\$

Bring both sides of the equation to the power of 2

$( { - 8})^(2) + ({2 - a})^(2) = ({ - 1 - a})^(2) + ({2 + 3})^(2) \\$

$64 + 4 - 4a + {a}^(2) = 1 + 2a + {a}^(2) + 25 \\$

${a}^(2) - 4a + 68 = {a}^(2) + 2a + 26$

Subtract sides -26

${a}^(2) - 4a + 68 - 26 = {a}^(2) + 2a + 26 - 26 \\$

${a}^(2) - 4a + 42 = {a}^(2) + 2a$

Subtract sides -a²

${a }^(2) - {a}^(2) - 4a + 42 = {a}^(2) - {a}^(2) + 2a \\$

- 4a + 42 = 2a

Plus sides 4a

4a - 4a + 42 = 2a + 4a

42 = 6a

Divided sides by 6

$(42)/(6) = (6)/(6)a \\$

a = 7

_________________________________

And we're done.....♥️♥️♥️♥️♥️