Question

I NEED HELP ON THIS PLEASE!!

Below are the test scores for Ms. Brown's 1st and 2nd period math classes. Analyze the data and choose EACH correct statement:

1st period (Class A): 10, 15, 20, 25, 30, 35, 40

2nd period (Class B): 7, 12, 17, 25, 33, 38, 43

The standard deviation for Class A is 10

The standard deviation for Class B is 12.615

These are the options:

- The mean (average) score for each class is the SAME.

-The mean (average) score for each class is DIFFERENT.

- The variance for Class A is 125.

- The variance for Class B is 159.14.

- Class A has a greater spread.

- Class B has a greater spread.

- Based on the data, a score of 8 is more likely in Class B than Class A.

- If graphed, Class B would look more like the red graph below and Class A would look more like the blue one.

Answer 1

hope that helps

Explanation:

- If graphed, Class B would look more like the red graph below and Class A would look more like the blue one.

- Based on the data, a score of 8 is more likely in Class B than Class A.

- Class A has a greater spread.