Question

There are 0.45 moles of Kr gas at a pressure of 1.35 atm and a temperature of 35°C. What volume would this gas occupy? (R= 0.0821 Mh/*))

Answer 1

Apply ideal gas equation

• PV=nRT
• V=nRT/P
• V=0.45(0.0821)(273+35)/1.35
• V=0.45(0.0821)(308)/1.35
• V=8.42L

Answer 2

Use ideal gas equation

• PV=nRT
• 1.35V=0.45(308)(0.0821)
• 135V=11.379
• V=8.4L