Question

A plane takes off from a runway and begins its climb. The plane takes off at a constant acceleration of 20 LaTeX: m /s^{2} . Once it reaches altitude it moves at 246 m/s, and maintains that speed. If it continues at this speed for 93 min, how far would the plane have traveled from the time took off?

Answer 1

The plane have traveled 1512.9 m from the time took off

Explanation:

Acceleration
`a = 20m/s^2`

Initial speed = u = 0

Final speed = v = 246 m/s

Time = t = 93

We are supposed to find how far would the plane have traveled from the time took off

We will use equation of motion

`v^2=u^2+2as\\(246)^2=2* 20 * s\\((246)^2)/(2 * 20)=s\\1512.9 m=s`

Hence The plane have traveled 1512.9 m from the time took off