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Solve 2sin (3x) – 1 = 0 on the interval [0, 2π).

Solve 2sin (3x) – 1 = 0 on the interval [0, 2π).
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Solve 2sin (3x) – 1 = 0 on the interval [0, 2π).

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User John Resig
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Answer:

Explanation:

Here uu go

Solve 2sin (3x) – 1 = 0 on the interval [0, 2π).-example-1
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User Zerocog
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