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Sin3x + sin x = COS x; [0, pi/2]

Sin3x + sin x = COS x; [0, pi/2]
asked 18.0k views
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Sin3x + sin x = COS x; [0, pi/2]

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User Roman Podpryatov
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8.3k points

1 Answer

7 votes

Answer:

The answer is 0

Subtract cosine x from both sides of this equation.

sin(3x) + sin(x) - cos(x) = 0

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User Verbranden
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