Question

You release a ball from rest at the top of a ramp. 6 s later it is moving at 4.0

m/s. What is the acceleration? (in meters per second squared) *
Your answer

Answer 1

`a = (vf - vi)/(t)`

here initial velocity vi=0 as ball release from rest

the final velocity is vf=4.0

time is t=6

so putting all these values in above equation

`a = ( 4.0- 0)/(6)`

`a = 0.6667m \s {}^(2)`