Question

Please help, circle theorems

Answer 1

AOD=180°-(32°+90°)=180°-122°=58°(OAD=90°, bcs R (OA) perpendicular on tg (AD)

AC=AOC=AOD=58°

ABC=AC/2=AOC/2=58°/2=29°(the angle inscribed in the circle is half of the arc of the circle under it )

Hope it helps!