Question

Unknown element has two isotopes. Isotope A has a mass of 34 amu and abundance of 52%, isotope B has a mass of 33 amu and abundance of 48%. Find average atomic mass of this element and express your

Answer 1

x = 33.52 amu

Step-by-step explanation:

It is given that,

Isotope A has a mass of 34 amu and an abundance of 52%, isotope B has a mass of 33 amu and an abundance of 48%.

Let x is the average atomic mass of this element. It can be calculated as follows :

`x=52\%\ \text{of}\ 34+48\%\ \text{of}\ 33\\\\x=(52)/(100)* 34+(48)/(100)* 33\\\\x=0.52* 34+0.48* 33\\\\x=33.52\ \text{amu}`

So, the average atomic mass of this element is 33.52 amu.