Question

A driver of a car traveling at -15m/s applies the brakes, causing a uniform acceleration of +2.0m/s2. If the brakes are applied for 2.5s, what is the velocity of the car at the end of the braking period? How far has the car moved during the braking period?

Answer 1

Given :

Initial velocity, u = -15 m/s.

Acceleration , a = 2 m/s².

Time taken to applied brake, t = 2.5 s.

To Find :

The velocity of the car at the end of the braking period.

How far has the car moved during the braking period.

Solution :

By equation :

`v = u+at\\\\v=-15 + 2* 2.5\\\\v=-10 \ m/s`

Now, distance covered by car is :

`s=ut+(at^2)/(2)\\\\s=(-15)(2.5)+(2(2.5)^2)/(2)\\\\s=-31.25\ m`

Hence, this is the required solution.