Question

HELPPPPPPPPP

50. How many joules of heat must be absorbed by 0.375 kg of water to raise its temperature by 45.0 to 70.0°C. Specific heat of water is 4.184 J/gC or 1.0 cal/gC
51. What mass of water can be heated from 25.0 to 50.0°C by the adding of 2825 Joules?(Cp of H2O=4.184 J/g °C)

Answer 1

50. 54,915 J

51. 27.0 g

Step-by-step explanation:

The dimensional analysis tells you how to compute these. Multiplying specific heat, J/(g·°C), by the product of mass and temperature change will give you energy.

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50. (375 g)((70 -45) °C)(4.184 J/(g·°C)) = 54,915 J

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51. M((50 -25)°C)(4.184 J/(g·°C)) = 2825 J

M = 2825/104.6 g ≈ 27.0 g