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Suppose that four times the square of a number equals 20x that number.what is the number​

asked
User EeeeeK
by
7.8k points

2 Answers

0 votes

Answer:

Number = x

4x^2 = 20x

4 x^2 -20x = 0

Dividing both sides by 4

x^2 -5x =0

(x -5) (x +0) = 0

x = 5

and x = 0

Explanation:

answered
User Eugene Astafiev
by
8.4k points
6 votes

Answer:

4X^2=20X

4X^2-20X=0

4X(X-5)=0

4X=0

X=0

X-5=0

X=5 SOLUTION

PROOF

4*5^2=20*5

4*25=100

100=100

Explanation:

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answered
User IamIC
by
8.3k points

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