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What is the distance of PQ
with endpoints P (–3, 4) and Q (5, –8)

1 Answer

4 votes

Answer:square root of 208

Step-by-step explanation: the difference of the X values is 8 and the diff of Y values is 12. 8 squared is 64 and 12 squared is 144. If both are added and square rooted, then it becomes sqrt 208

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User Sdesvergez
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