Question

265. The perimeter of a rectangle

is 58 meters. The width of the
rectangle is five meters less than
the length. Find the length and the
width of the rectangle.

Answer 1

L = 17 m, W = 12 m

Step-by-step explanation:

W = (L - 5) m

P = 2(L + W) = 58 m

Substitute W = L - 5 from the first equation into the second equation and get L:

2[L + (L - 5)] = 58

2(2L - 5) = 58

2L - 5 = 58/2 = 29

L = (29 + 5)/2 = 17

Then W = L - 5 = 17 - 5 = 12