asked 42.0k views
21 votes
1. How many grams of NaCl are required to prepare 3.5 L of 2.50 % (w/v) sodium chloride solution? A. 87.5 g B. 0.71 g C. 12.5 g D. 62.5 g​

1 Answer

4 votes

Answer:

87.5

Step-by-step explanation:

3.5 L to g would be 3500

3500*2.5%= 87.5 g

answered
User MLeblanc
by
8.4k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.