asked 223k views
4 votes
A spring exerts a force of 1000 pounds when stretched five feet from its equilibrium

position. How much work is needed to stretch the spring six feet from its equilibrium position?

asked
User Nk Abram
by
8.2k points

2 Answers

3 votes

Answer: 1,200 pounds

5 feet = 1,000 pounds

5 x 200 = 1,000

6 feet = 1,250 pounds

6 x 200 = 1,200

Answer = 1,200 pounds

answered
User Tennyson
by
7.4k points
5 votes

1000 pounds / 5 feet = 200 pounds per foot.

200 pounds per foot x 6 feet = 1200 pounds.

The answer is 1,200 pounds.

answered
User YTKColumba
by
7.6k points

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