Question

Find the value(s) of "k" that will cause the equation 4x^2 +kx + 4 to have one real solution.

Answer 1

Answer: k = {8, -8}

Explanation:

In order for a quadratic equation to have exactly one solution, the discriminant must equal zero. → b² - 4ac = 0

4x² + kx + 4 = 0

↓ ↓ ↓

a=4 b=k c=4

b² - 4ac = 0

k² - 4(4)(4) = 0

k² = 64

k = √64

k = ± 8