Question

Write the equation of a line perpendicular to 8x - 7y= -6 that passes through the point (-8,6).

The equation of the line is y=

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Answer 1

y= -7/8x – 1

Explanation:

• the first equation would be y= 8/7 + 6/7
• the perpendicular slope would be -8/7
• and I solved for b by plugging in what I know for y=mx+b
• which is 6= -7/8(-8) + b
• simplify so 6 = 7 + b
• subtract 7 on both sides to get b = -1