We develop an equation for the given situation by first writing the general equation for lines, 
 y = mx + b 
Substituting to this given the values given above, 
 (1990) 430 = b 
 (2000) 400 = m(10) + 430 
The value of m from the equation in 2000 is -3. Thus, the equation of that relates the variables is, 
 y = -3x + 430