Register

5 - 2y + 1/3 + y^3 - 10y for y = 4 I solved this equation but I'm not sure if I got the answer correct and if I messed up somewhere when I was solving it then I got my answ…

5 - 2y + 1/3 + y^3 - 10y for y = 4 I solved this equation but I'm not sure if I got the answer correct and if I messed up somewhere when I was solving it then I got my answ…
asked 201k views
2 votes
5 - 2y + 1/3 + y^3 - 10y for y = 4

I solved this equation but I'm not sure if I got the answer correct and if I messed up somewhere when I was solving it then I got my answer wrong. So if someone could please help me that would be very much appreciated!!!!!

asked
User Zeal
by
8.6k points

1 Answer

2 votes

Answer:

4

Explanation:

i think i am correct but if im not sorry

answered
User Charelle
by
8.7k points
← Prev Question Next Question →

Related questions

User Bofeng
asked Oct 21, 2017 158k views
3x^2 + 5x =8 Solve with the quadratic formula. I messed up somewhere in my solving... Steps would be great~!
Bofeng asked Oct 21, 2017
by Bofeng
7.4k points
2 answers
5 votes
158k views
User NYCBilly
asked May 13, 2020 49.3k views
I need to know the pounds required. I started some of the steps but I feel like I messed up somewhere ​
NYCBilly asked May 13, 2020
by NYCBilly
8.3k points
1 answer
2 votes
49.3k views
Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!