Question

A rocket blasts off and moves straight upward from the launch pad with constant acceleration. After 3.0 s the rocket is at a height of 87 m. Part A What is the magnitude of the rocket's acceleration

Answer 1

~19.33m/s^2

Step-by-step explanation:

`D=v*t-(1)/(2)a*t^(2) \\v=0m/s\\D=(1)/(2)a*t^(2)\\(D*2)/(t^(2) ) =a\\(87*2)/(3^(2) ) =a\\174/9=19.333 m/s^2`