Question

How many grams of barium chloride (BaCl2) are there in 0.187 mol?
0.187 mol

Answer 1

38.9 grams of
`BaCl_2`

Step-by-step explanation:

0.187 mol BaCl2 x
`(208 g)/(1 mol)`

0.187 m x 208 g/m

0.187 x 208 g

38.896 g --> 38.9 g BaCl2