Question

Factor completely P(x) = 81x^4 − 256

Answer 1

`(3x+4)(3x-4)(9x^2+16)`

Explanation:

Given
`p(x)=81x^4-256`

Factor using difference of squares

`p(x)=(9x^2-16)(9x^2+16)`

Note that the factor
`(9x^2-16)` can still be factored using, again, difference of squares. Thus,

`p(x)=(3x+4)(3x-4)(9x^2+16)`