(40x^3y^6)/(-8x^2y) PLEASE HELP!

Question

`(40x^3y^6)/(-8x^2y)` PLEASE HELP!

Answer 1

`\huge\boxed{(40x^3y^6)/(-8x^2y)=-5xy^5}`

Explanation:

`(40x^3y^6)/(-8x^2y)=(40)/(-8)\cdot(x^3)/(x^2)\cdot(y^6)/(y)\\\\\text{use}\ (a^n)/(a^m)=a^(n-m)\\\\=-5x^(3-2)y^(6-1)=-5x^1y^5=-5xy^5`

Answer 2

here's my answer...........