Question

(2,1)

Which of the following could be the quadratic function graphed in the xy-plane above?
f(x) = 2x2
f(x) = x2 + 1
f(x) = (x - 2)2 + 1
f(x) = (x - 1)2 + 2

Answer 1

the correct answer is f(x)=(x-2)^2 + 1

Explanation:

lets loof for f(2) :

f(2)=(2-2)^2 + 1

f(2)=(0)^2 + 1

f(2)= 1 ---> (2,1)