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Given \sqrt{27}+\sqrt{108} 27 + 108 =27^{\frac{1}{2}}+108^{\frac{1}{2}}=27 2 1 +108 2 1 3^{\frac{1}{2}}\cdot9^{\frac{1}{2}}+3^{\frac{1}{2}}\cdot36^{\frac{1}{2}}3 2 1 ⋅…
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Given \sqrt{27}+\sqrt{108} 27 + 108 =27^{\frac{1}{2}}+108^{\frac{1}{2}}=27 2 1 +108 2 1 3^{\frac{1}{2}}\cdot9^{\frac{1}{2}}+3^{\frac{1}{2}}\cdot36^{\frac{1}{2}}3 2 1 ⋅…
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Mar 1, 2021
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Given \sqrt{27}+\sqrt{108}
27
+
108
=27^{\frac{1}{2}}+108^{\frac{1}{2}}=27
2
1
+108
2
1
3^{\frac{1}{2}}\cdot9^{\frac{1}{2}}+3^{\frac{1}{2}}\cdot36^{\frac{1}{2}}3
2
1
⋅9
2
1
+3
2
1
⋅36
2
1
3\cdot3^{\frac{1}{2}}+6\cdot3^{\frac{1}{2}}3⋅3
2
1
+6⋅3
2
1
18\cdot3^{\frac{1}{2}}18⋅3
2
1
Mathematics
high-school
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Answer: I need points sorry that I'm to dumb to answer.
Explanation:
Mauker
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Mar 5, 2021
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Mauker
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