Question

A plastic container holds 3 red balls, 2 green balls, and 3 yellow balls. What is the probability of choosing a green ball, replacing it, and then choosing a yellow ball?

Answer 1

`0.09375`

Explanation:

the total number of balls = 3 + 3 + 2 = 8

Let p be the probability of choosing a green ball, replacing it, and then choosing a yellow ball.

`p=p\left( \text{choosing a green ball} \right) +p\left( \text{choosing a yellow ball} \right)`

`=(2)/(8) * (3)/(8)`

`=(6)/(64)`

`= 0.09375`