Question

Work out an equation of the straight line with gradient 3 that passes through the point with coordinates (2, 4).

Answer 1

The answer is

`\huge \boxed{y = 3x - 10}`

Explanation:

To find an equation of a line given the slope and a point we use the formula

`y - y_1 = m(x - x_1)`

where

m is the slope

( x1 , y1) is the point

From the question the point is (2, 4) and the slope is 3

The equation of the line is

`y - 4 = 3(x - 2) \\ y + 4 = 3x - 6 \\ y = 3x - 6 - 4`

We have the final answer as

`y = 3x - 10`

Hope this helps you