Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'. Triangle A,B,C with vertices at A(negative 3, 6), B(2, 9), and C(1, 1)

Question

asked Jul 18, 2021 144k views

1 Answer

Brennan Hoeting · Answer 1 · 2021-07-22T03:43:11+0000

Note: Consider we need to find the vertices of the triangle A'B'C'

Given:

Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.

Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).

To find:

The vertices of the triangle A'B'C'.

Solution:

If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

$(x,y)\to (y,-x)$

Using this rule, we get

$A(-3,6)\to A'(6,3)$

$B(2,9)\to B'(9,-2)$

$C(1,1)\to C'(1,-1)$

Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).