0.12M NaOH solution to neutralize Oxalic acid solution. you will need the molecular weight of the Oxalic acid

Question

asked Jan 3, 2021 9.1k views

1 Answer

JTiKey · Answer 1 · 2021-01-07T02:34:32+0000

Answer:

2 NaOH (aq) + H2C2O4(aq) Na2C2O4(aq) + 2H2O (l) Moles of NaOH used = Molarity x Volume (L) = 0.12 mole/L x 0.025

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