Question

3. A student takes an object with an accepted mass of 200.00 grams and masses it on his own balance. He

records the mass of the object as 196.5 g. What is his percent error?
I

Answer 1

The answer is 1.75 %

Step-by-step explanation:

The percentage error of a certain measurement can be found by using the formula

`P(\%) = (error)/(actual \: \: number) * 100\% \\`

From the question

actual number = 200 g

error = 200 - 196.5 = 3.5

We have

`p(\%) = (3.5)/(200) * 100 \\`

We have the final answer as

1.75 %

Hope this helps you