Question

How many moles is 8.7 x 1027 atoms of Helium?

Answer 1

14500.

Step-by-step explanation:

1) Avlgadro's number is 6.022*10²³;

2) 1 mol is 6.022*10²³ atoms of Hellium, then 8.7*10²⁷ atoms is

`3) \ (87*10^(26))/(6*10^(23))=14.5*10^3=14500[moles].`