If p(x) = 2x2 – 4x and q(x) = x – 3, what is (p circle q) (x)?

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asked Apr 2, 2021 27.5k views

1 Answer

Nico Andrade · Answer 1 · 2021-04-05T19:48:35+0000

Solution:

(p o q) = p(q(x))
p(q(x)) = 2(x - 3)^2 - 4(x - 3)
======= 2(x - 3)(x - 3) - 4(x - 3)
======= 2(x^2 - 6x + 9) - 4(x -3)
(p o q) = 2x^2 - 10x + 30
(p o q) = 2[x^2 - 5x + 15]

If p(x) = 2x2 – 4x and q(x) = x – 3, what is (p circle q) (x)?

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