Question

Six multiplication problems involved in solving 325 x 89

Answer 1

(300*80) + (300*9) + (20*80) + (20*9) + (5*80) + (5*9) = 28925

Explanation:

Given;

325 x 89

Expand 325 = 300 + 20 + 5

Expend 89.0 = 80 + 9

now multiple to two expanded numbers;

(300 + 20 + 5) x (80 + 9)

distribute the number accordingly as follows;

(300*80) + (300*9) + (20*80) + (20*9) + (5*80) + (5*9), now we have Six multiplication problems.

= 24,000 + 2700 + 1600 + 180 + 400 + 45

= 28925