Question

The sum of 3 consecutive integers is 120. What is the greatest of these integers? HELP ME IT'S DUE TODAY!!!

Answer 1

41

Explanation:

The consecutive integers are increasing by 1

x ← the smallest integer

x+1 ← the middle integer

x+1+1 = x+2 ← the largest integer

x + x+1 + x+2 = 120

3x + 3 = 120

÷3 ÷3

x + 1 = 40

-1 -1

x = 39

x+2 = 39 + 2 = 41