Question

There are 3 consecutive integers that have a sum of 36. What are the integers?

Answer 1

11, 12, 13

Explanation:

The consecutive integers are increasing by 1

k ← the smallest integer

k+1 ← the middle integer

k+1+1 = k+2 ← the largest integer

k + k+1 + k+2 = 36

3k + 3 = 36

÷3 ÷3

k + 1 = 12

-1 -1

k = 11

k+1 = 11 + 1 = 12

k+2 = 11 + 2 = 13