Question

3x^2+9x+6=0
Solve for quadratic formula

Answer 1

`x=-1 ,-2`

Explanation:

Quadratic Formula:
`x=(-b \pm √(b^2-4ac) )/(2a)`

Step 1: Define

3x² + 9x + 6 = 0

a = 3

b = 9

c = 6

Step 2: Substitute and Evaluate

`x=(-9 \pm √(9^2-4(3)(6)) )/(2(3))`

`x=(-9 \pm √(81-72) )/(6)`

`x=(-9 \pm √(9) )/(6)`

`x=(-9 \pm 3 )/(6)`

`x=(3(-3 \pm 1) )/(6)`

`x=(-3 \pm 1)/(2)`

`x=(-2)/(2) ,(-4)/(2)`

`x=-1 ,-2`