Question

Water has a specific heat of 4.184 J/g°C and requires 23,000 J of heat to raise the

temperature 68° C. What is the mass of the water?

Answer 1

`m=80.840 kg`

Explanation:

Given Data,

Q=23000 J

c=4.184 J/g °c

Δt= 68 °c

m=?

By using this equation,

Q=mcΔt

`23000=m* 4.184* 68\\\\m=(23000)/(4.184*68) \\\\\\m=80.840 kg`