Question

During a school tournament, Team A had 10 of its 12 team members present.

Team B had 13 of its 15 players present.
Which team had the lesser percent of its team present at the tournament?

Answer 1

Team A.

Explanation:

We know that Team A had 10 of its 12 members present.

We can write this as the following fraction:

`A=10/12`

We can convert this to a decimal by dividing the two numbers. Use a calculator:

`A\approx.8333`

And we can convert this to a percent by moving the decimal too places to the right and by adding a percent sign:

`A\approx83.33\%`

So, about 83.33% of members on Team A was present.

We know that Team B had 13 of its 15 members present.

We can write this as the following fraction:

`B=13/15`

Again, we can convert this to a decimal by dividing the two numbers:

`B\approx 0.8667`

Change this to a percent:

`B\approx86.67\%`

So, Team A had a participation rate of 83.33% while Team B had a participation rate of 86.67%.

So, the team that had the lesser percent of the team present at the tournament is Team A.

And we're done!