Question

Find 3 consecutive integers with a sum of -36

Answer 1

-13, -12, -11

Explanation:

Step 1: Define

1st consecutive integer - x

2nd consecutive integer - x + 1

3rd consecutive integer - x + 2

Step 2: Set up equation

x + x + 1 + x + 2 = -36

Step 3: Solve for x

1. Combine like terms: 3x + 3 = -36
2. Subtract 3 on both sides: 3x = -39
3. Divide both sides by 3: x = -13

Step 4: Find other integers

1st consecutive integer = -13

2nd consecutive integer = -13 + 1 = -12

3rd consecutive integer = -13 + 2 = -11