Answer:
Number of atoms in 52g of He is 7.829X10^24.
Step-by-step explanation:
Solution,
Given,
No of mole of atoms (NA) = 6.023x10^24.
Mass ogiven helium=52g
Atomic mass of helium=4
Lets do sep by step,
1) No. of atom in 52g of He.
= NAxmass/At.mass
= 6.023X10^23x52/4
= 7.829 x 10^24.