Question

I got this wrong. not sure where I went wrong​

Answer 1

`\left( x-2\right)^(2) +\left( y-6\right)^(2) =12`

Explanation:

Formula ………………………………………………………………………

The equation of a circle with center (a , b) and radius r is :

`\left( x-a\right)^(2) +\left( y-b\right)^(2) =r^(2)`

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Now ,let’s apply what we have learnt:

The equation of the circle with center (a , b) = (2 , 6) and radius r = 2√3 is :

`\left( x-2\right)^(2) +\left( y-6\right)^(2) =\left( 2√(3) \right)^(2)`

`\Longleftrightarrow \left( x-2\right)^(2) +\left( y-6\right)^(2) =12`

`\text{Note :} \left( 2√(3) \right)^(2) =2^(2)* √(3)^(2) =4*3=12`